Answer:
\({\angle}ABC=41^{\circ}\)
Step-by-step explanation:
From, the given figure, it is given that \({\angle}BAC=72^{\circ}\) and \({\angle}BCD=113^{\circ}\).
Using the exterior angle property in ΔABC, we have
\({\angle}ABC+{\angle}BAC={\angle}BCD\)
⇒\({\angle}ABC+72^{\circ}=113^{\circ}\)
⇒\({\angle}ABC=113^{\circ}-72^{\circ}\)
⇒\({\angle}ABC=41^{\circ}\)
Therefore, the measure of \({\angle}B\) is \(41^{\circ}\).
