4(x+1)-ax=x+5 solve for x
4(x + 1) - ax = x + 5
4(x) + 4(1) - ax = x + 5
4x + 4 - ax = x + 5
- x - x
3x + 4 - ax = 5
- 4 - 4
3x - ax = 1
x(3) - x(a) = 1
x(3 - a) = 1
3 - a 3 - a
x = 1/(3 - a)
\(4(x+1)-ax=x+5\)
\(4x+4-ax=x+5\) \(Expand\)
\(4x-ax=x+5-4\) \(Subtract \ 4 \ from \ both \ sides\)
\(4x-ax=x+1\)
\(4x=x+1+ax\) \(Add \ ax \ to \ both \ sides\)
\(4x-x=1+ax\) \(Subtract \ x \ from \ both \ sides\)
\(3x=1+ax\)
\(3x-ax=1\) \(Subtract \ ax \ from \ both \ sides\)
\(x(3-a)=1\)
\(x= \dfrac{1}{3-a}\)