4300242202
Answered

Suppose ∠A and ∠B are complementary angles, m∠A = (3x + 5)°, and

m∠B = (2x – 15)°. Solve for x and then find m∠A and m∠B.

Verified Answer :

Panoyin

m∠A + m∠B = 90
(3x + 5) + (2x - 15) = 90
(3x + 2x) + (5 - 15) = 90
                  5x - 10 = 90
                      + 10  + 10
                         5x = 100
                          5      5
                           x = 20

m∠A = 3x + 5
m∠A = 3(20) + 5
m∠A = 60 + 5
m∠A = 65

m∠B = 2x - 15
m∠B = 2(20) - 15
m∠B = 40 - 15
m∠B = 25

m∠A + m∠B = 90

\((3x + 5) + (2x - 15) = 90\)

\((3x + 2x) + (5 - 15) = 90\)

\(5x - 10 = 90\)

\(5x - 10 +10 = 90+10\)

\(5x = 100\)

\(5x/5 = 100/5\)      \(Divide \ both \ sides \ by \ 5\)

\(x = 20\)                 \(Solutions\)

m∠A = \(3x + 5\)     \((x=20)\)

m∠A = \(3(20) + 5\)          \(Substitute \ x \ for \ 20\)

m∠A = \(60 + 5\)               \(Simplify\)

m∠A = \(65\)


m∠B = \(2x - 15\)

m∠B = \(2(20) - 15\)

m∠B = \(40 - 15\)

m∠B = \(25\)

Related Questions