solve: 2/7(x-5)=-2+2/5x
2/7(x-5)=-2+2/5xOpening brackets;2/7x-10/7=-2+2/5x2/7x-2/5x=-2+10/7=\(\frac{10x-14x}{35} = \frac{-14}{7} + \frac{10}{7}\)\(\frac{-4x}{35} = \frac{-4}{7}\)Multiplying each side by 35;-4x=-4(5)-4x=-20x=5