Which of the following is a solution of x2 − 10x = –36? negative 5 minus i square root of 10 5 plus i square root of 61 negative 5 minus i square root of 11 5 plus i square root of 11
x^2 - 10x + 36 = 0; We use the quadratic formula: x = ( - b + or - i\(\sqrt{ -b^{2}+4ac }\))/ (2a); We have a = 1; b = -10; c = 36; Then, x = ( 10 + or -i\(\sqrt{44}\))/2 = 5 + or - \(\sqrt{11}\))/2 ;
