On the first spin, the probability that any specific number from 1 to nine inclusive is 1/9. On the second spin, the same value of probability applies. If the spinner is fair, the result from the first spin has no effect on the result of the second spin. therefore:
\(P(3\ then\ 5)=\frac{1}{9}\times\frac{1}{9}=\frac{1}{81}\)
