Verified Answer :

sweetart123

The answer would be A) tan A, because of SOHCAHTOA (if you don't know this, it means SOH) sin=opposite/hypotenuse, CAH) cos=adjacent/hypotenuse, and TOA) tan=opposite/adjacent).

calculista

we know that

In the right triangle ABC

\(sin(A)=\frac{BC}{AC}= \frac{a}{b}\)

\(cos(A)=\frac{AB}{AC}= \frac{c}{b}\)

\(tan(A)=\frac{BC}{AB}= \frac{a}{c}\)

\(sin(C)=\frac{AB}{AC}= \frac{c}{b}\)

\(cos(C)=\frac{BC}{AC}= \frac{a}{b}\)

\(tan(C)=\frac{AB}{BC}= \frac{c}{a}\)

therefore

the answer is the option A

\(tan(A)\)

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