how to find the derivative of e^3㏑(x²)
\(f(x)=e^{3\ln x^2}\\\\f'(x)=e^{3\ln x^2}\cdot\dfrac{3}{x^2}\cdot2x=e^{3\ln x^2}\cdot\dfrac{6}{x}=\dfrac{6e^{3\ln x^2}}{x}\\\\\\but\ e^{3\ln x^2}=e^{\ln (x^2)^3}=e^{\ln x^6}=x^6\ where\ x eq0\\\\therefore\ f'(x)=6x^5\)
