Answer: The required value of \(f^{'-1}(\pi+7)\) is 2.
Step-by-step explanation: We are given the following value of a function f :
\(f(2)=\pi+7.\)
We are to find the value of \(f^{-1}(\pi+7).\)
We know that
For any function g(x) = y,
\(g^{-1}(y)=x.\)
Applying the above rule in equation (i), we get
\(f(2)=\pi+7\\\\\Rightarrow f^{-1}(\pi+7)=2.\)
Thus, the required value of \(f^{'-1}(\pi+7)\) is 2.
