In the figure, ΔABC ~ ΔDEF. Solve for x.
Answer:
\(x=5\)
Step-by-step explanation:
It is given that ΔABC is similar to ΔDEF, thus using the similarity postulate, we have
\(\frac{CB}{EF}=\frac{AB}{ED}\)
⇒\(\frac{24}{6}=\frac{20}{x}\)
On Cross multiplying, we get
⇒\(x=\frac{20{\times}6}{24}\)
⇒\(x=\frac{20}{4}\)
⇒\(x=5\)
Thus, the value of x will be 5.