Answer:
\(10.1536\times 10^{-1}\approx 1.02\) grams.
Step-by-step explanation:
We have been given that a closed container has \(6.08\times 10^{23}\) atoms of a gas. Each atom of the gas weighs \(1.67\times 10^{-24}\) grams.
To find the total mass, in grams, of all the atoms of the gas in the container, we will multiply number of atoms with mass of each atom.
\(\text{Total mass}=6.08\times 10^{23}\times 1.67\times 10^{-24}\)
Using exponent property \(a^b\times a^c=a^{b+c}\), we will get:
\(\text{Total mass}=6.08\times 1.67\times 10^{23}\times 10^{-24}\)
\(\text{Total mass}=10.1536\times 10^{23+(-24)}\)
\(\text{Total mass}=10.1536\times 10^{-1}\)
\(\text{Total mass}=10.1536\times\frac{1}{10}\)
\(\text{Total mass}=1.01536\)
\(\text{Total mass}\approx 1.02\)
Therefore, the approximate total mass, in grams, of all the atoms of the gas in the container is \(10.1536\times 10^{-1}\approx 1.02\) grams.
