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sscheylfuent
sscheylfuent sscheylfuent
  • 19-08-2016
  • Mathematics
Answered

Triangle ABC has three sides with these lengths: AB = 9, BC = 40, and CA = 41. What is the value of cos C? A. 9/41 B. 40/9 C. 40/41 D. 9/40

Verified Answer :

dalendrk
dalendrk dalendrk
  • 20-08-2016

It's a rectangular triangle because:

9² + 40² = 41²
81 + 1600 = 1681
1681 = 1681

Answer: C. cos∡C = 40/41

Answer Link
Anonymous Anonymous
  • 27-08-2016

The answer is letter C which is 40/41. If you draw a triangle the sides found in the cos C is BC which is equal to 40 and the CA which is equal to 41 or the 40/41. It can not be the AB since it is in the opposite side of the cos C.

Answer Link

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