Iron has a density of 7.9 g/cm3. What is the mass of a cube of iron with the length of one side equal to 55.0 mm?
Density is a value for
mass, such as kg, divided by a value for volume, such as m3. Density is a
physical property of a substance that represents the mass of that substance per
unit volume. To find the mass of the substance, we need to multiply the volume occupied by the substance.
Mass = Density x Volume
Mass = 7.9 g/cm^3 (5.5 cm)^3
Mass = 43.45 g
Answer:
Mass, m = 1.31 kg
Explanation:
It is given that,
Density of iron, \(d=7.9\ g/cm^3\)
Side of cube, a = 55 mm = 5.5 cm
We need to find the mass of the cube of iron. Mass per unit volume is called the density of the substance. It is given by :
\(d=\dfrac{m}{V}\)
\(d=\dfrac{m}{a^3}\)
\(m=d\times a^3\)
\(m=7.9\times (5.5)^3\)
m = 1314.36 grams
or
m = 1.31 kg
So, the mass of the iron cube is 1.31 kg. Hence, this is the required solution.