a mixture of oxygen, hydrogen, and nitrogen gases exerts a total pressure of 282 kpa. if the partial pressures of oxygen and hydrogen are 110 kpa and 106 kpa respectively, what is the partial pressure exerted by nitrogen?

Verified Answer :

pressures oxygen and hydrogen +  pressure nitrogen

110 Kpa + 106 Kpa = 216 Kpa

Partial pressure:

total pressure -  exerted by nitrogen:

282 Kpa - 216 Kpa

= 66 Kpa

hope this helps!

Answer :  The partial pressure of \(N_2\) is, 66 Kpa

Solution :

According to the Dalton's law, the total pressure of the gas is equal to the sum of the partial pressure of the mixture of gasses.

\(P_T=p_{N_2}+p_{O_2}+p_{H_2}\)

where,

\(P_T\) = total partial pressure = 282 Kpa

\(P_{N_2}\) = partial pressure of nitrogen = ?

\(P_{O_2}\) = partial pressure of oxygen = 110 Kpa

\(P_{H_2}\) = partial pressure of hydrogen = 106 Kpa

Now put all the given values is expression, we get the partial pressure of the nitrogen gas.

\(282Kpa=p_{N_2}+110Kpa+106Kpa\)

\(p_{N_2}=66Kpa\)

Therefore, the partial pressure of \(N_2\) is, 66 Kpa