a mixture of oxygen, hydrogen, and nitrogen gases exerts a total pressure of 282 kpa. if the partial pressures of oxygen and hydrogen are 110 kpa and 106 kpa respectively, what is the partial pressure exerted by nitrogen?
pressures oxygen and hydrogen + pressure nitrogen
110 Kpa + 106 Kpa = 216 Kpa
Partial pressure:
total pressure - exerted by nitrogen:
282 Kpa - 216 Kpa
= 66 Kpa
hope this helps!
Answer : The partial pressure of \(N_2\) is, 66 Kpa
Solution :
According to the Dalton's law, the total pressure of the gas is equal to the sum of the partial pressure of the mixture of gasses.
\(P_T=p_{N_2}+p_{O_2}+p_{H_2}\)
where,
\(P_T\) = total partial pressure = 282 Kpa
\(P_{N_2}\) = partial pressure of nitrogen = ?
\(P_{O_2}\) = partial pressure of oxygen = 110 Kpa
\(P_{H_2}\) = partial pressure of hydrogen = 106 Kpa
Now put all the given values is expression, we get the partial pressure of the nitrogen gas.
\(282Kpa=p_{N_2}+110Kpa+106Kpa\)
\(p_{N_2}=66Kpa\)
Therefore, the partial pressure of \(N_2\) is, 66 Kpa