why is log of 1 with base b is 0
\(De finition\ of\ logarithm:\log_ab=c\iff a^c=b\\where\ a > 0,\ a eq1,\ b > 0\ and\ c\in\mathbb{R}\\\\therefore\\\\\log_b1=0\ because\ b^0=1\ for\ b > 0\ and\ b eq1\)
