Verified Answer :

\(f(x) = -x^2 + 4\)

\(g(x) = 6x\)

\((g - f)(3) = 6(3) - (-(3)^2 + 4)\)

\((g - f)(3) = 18 - (-9 + 4)\) 

\((g - f)(3) = 18 - (-5)\)

\((g - f)(3) = 18 + 5\)

\((g - f)(3) = 23\)

dalendrk

f(x) = 4 - x²    Df: x∈R

g(x) = 6x  Dg: x∈R

Df = Dg therefore (g - f)(x) = g(x) - f(x)

(g - f)(3) = g(3) - f(3)

subtitute the value of x to equations:

g(3) = 6 · 3 = 18
f(3) = 4 - 3² = 4 - 9 = -5

(g - f)(3) = 18 - (-5) = 18 + 5 = 23

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