If y= x^3 + 1, find y when x= 2
y = x³ + 1subtitute x = 2 to the equationy = 2³ + 1 = 8 + 1 = 9
\(y = x^3 + 1\)\(y = 2^3 + 1\)\(8 + 1 = 9\)