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A balloon contains 6.0 moles of helium. A hole lets 4.0 moles of helium escape the balloon. How many atoms of helium remain in the balloon?


A.2.0 atoms

B.1.2 x10^24 atoms

C.6.02 x 10^24 atoms

D.6.0 Atoms

Verified Answer :

Dit is the answer to the question

Answer : The number of atoms of helium atom remain in the balloon are, \(1.2\times 10^{24}\)

Explanation : Given,

Moles of helium present in balloon = 6.0 mole

Moles of helium escape from balloon = 4.0 mole

First we have to calculate the moles of helium remains in the balloon.

Moles of helium remains in the balloon = Moles of helium present in balloon - Moles of helium escape from balloon

Moles of helium remains in the balloon = 6.0 - 4.0 = 2.0 mole

Now we have to calculate the number of helium atoms remain in the balloon.

As, 1 mole of helium atom remain in the balloon contains \(6.022\times 10^{23}\) number of helium atoms.

So, 2.0 mole of helium atom remain in the balloon contains \(2.0\times 6.022\times 10^{23}=12.044\times 10^{23}=1.2\times 10^{24}\) number of helium atoms.

Therefore, the number of helium atom remain in the balloon are, \(1.2\times 10^{24}\)

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