The dwarf seahorse hippocampus zosterae swims at a rate of 52.68 feet per hour.convert this speed to ines per minute
Acceleration is rate of change of velocity.
\(\large {\boxed {a = \frac{v - u}{t} } }\)
\(\large {\boxed {d = \frac{v + u}{2}~t } }\)
a = acceleration ( m/s² )
v = final velocity ( m/s )
u = initial velocity ( m/s )
t = time taken ( s )
d = distance ( m )
Let us now tackle the problem !
\(1 ~ foot = 30.48 ~ cm\)
\(1 ~ inch = 2.54 ~ cm\)
\(1 ~ foot = 12 ~ inches\)
\(\boxed {52.68 ~ feet = 52.68 \times 12 ~ inches = 632.16 ~ inches}\)
\(1 ~ day = 24 ~ hours\)
\(\boxed {1 ~ hour = 60 ~ minutes}\)
If the dwarf seahorse hippocampus zosterae swims at a rate of 52.68 feet per hour , then :
\(52.68 ~ feet/h = \frac{52.68 ~ feet}{1 ~ hour}\)
\(52.68 ~ feet/h = \frac{52.68 \times 12 ~ inches}{60 ~ minutes}\)
\(52.68 ~ feet/h = \frac{632.16 ~ inches}{60 ~ minutes}\)
\(\large {\boxed {52.68 ~ feet/h = 10.536 ~ inches/min} }\)
Grade: High School
Subject: Physics
Chapter: Kinematics
Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate