luckylulu03 luckylulu03

26-10-2014
Chemistry

Answered

NaHCO3 (s) + HC2H3O2 (aq) = NaC2H3O2 (aq) + H2O (I) + CO2 (g)
Using the above formula, if I used 0.100L of 0.83 M HC2H3O2 (aq) (0.83 mol per 1 L of solution), how much carbon dioxide would be produced?

Verified Answer :

26-10-2014

Moles=volumeconcentration
=0.1.83
=.083 Moles of HC2H3O2
Mole ratio between HC2H3O2 and CO2 is 1:1
This means .083 Moles of CO2

Mass =MolesRfm of CO2
=.083(12+16+16)
=3.7grams

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