if y varies directly as x, and y is 6 when x is 72, what is the value of y when x is 8? a. 1/9 b. 2/3 c. 54 d. 96
Answer:
The correct option is b.
Step-by-step explanation:
It is given that y varies directly as x.
\(y\propto x\)
\(y=kx\)
It is given that y is 6 when x is 72.
\(6=k\times 72\)
Divide both sides by 72.
\(\frac{1}{12}=k\)
The constant of proportionality is \(\frac{1}{12}\).
\(k=\frac{y}{x}\)
\(\frac{1}{12}=\frac{y}{8}\)
\(\frac{1}{12}\times 8=y\)
\(\frac{2}{3}=y\)
The value of y is \(\frac{2}{3}\). The correct option is b.