Answer:
\(\Rightarrow n\geq\frac{9-3c}{p}\)
Step-by-step explanation:
We have been given the inequality
−np − 6 ≤ 3(c − 5)
We will solve for n
So, firstly we will shift 6 on right hand side of the inequality we get:
\(-np\leq3(c-5)+6\)
Now, we will open the parenthesis on right hand side of the inequality;
\(-np\leq3c-15+6\)
\(-np\leq3c-9\)
\(-n\leq\frac{3c-9}{p}\)
\(\Rightarrow n\geq\frac{9-3c}{p}\)