\(\dfrac{2}{9}n+\dfrac{1}{2}=\dfrac{2}{3}(n+3)\ \ \ \ \ |multiply\ both\ sides\ by\ 18\\\\2\cdot2n+9=6\cdot2(n+3)\\\\4n+9=12(n+3)\\\\4n+9=12n+36\ \ \ \ |subtract\ 9\ from\ both\ sides\\\\4n=12n+27\ \ \ \ |subtract\ 12n\ from\ both\ sides\\\\-8n=27\ \ \ \ \ |divide\ both\ sides\ by\ (-8)\\\
=-\dfrac{27}{8}\\\
=-3\dfrac{3}{8}\)
