i need help!!! write an equation in point-slope form of the line through point j(4, –4) with slope 4. a. y 4=4(x 4) b. y 4=4(x-4) c. y-4=4(x 4) d. y 4=4(x-4)
Required equation is y - y1 = m(x - x1); where m = 4 and (x1, y1) = (4, -4)
y - (-4) = 4(x - 4)
y + 4 = 4(x - 4)
Answer:
The equation of line passing through (4,-4) and having slope '4' is: \(y+4=4(x-4)\)
Step-by-step explanation:
The equation of a line passing through a point \((x_{1},y_{1})\) and having slope 'm' is given by:
\(y-y_{1} =m(x-x_{1})\)
Here we are given that the line passes through the point (4,-4) and having slope 4.
⇒ \((x_{1},y_{1})=(4,-4)\) and \(m=4\)
Hence, the equation of line is:
\(y+4=4(x-4)\)