\(The vertex form:\ y=a(x-p)^2+q\ where\ (p;\ q)-coordinates\ of\ the\ vertex\)
The range of function \(y=ax^2+bx+c\)
if a > 0 then the range R = [q; ∞)
if a < 0 then the range R = (-∞; q]
We have: \(y=-3(x-1)^2-4\\\\a=-3 < 0\ and\ q=-4\)
therefore the range \(R=(-\infty;-4]\)
