what's the missing variable for 1/3n+3=-n-2
\(\frac{1}{3}\)n + 3 = -n - 2 Multiply both sides by 3 to cancel out the fraction n + 9 = -3n - 6 Add 3n to both sides4n + 9 = 6 Subtract 9 from both sides 4n = -3 Divide both sides by 4 n = \(- \frac{3}{4}\)
