Answer: \(1\dfrac{1}{13}\)
Step-by-step explanation:
Given : The wingspan of the butterfly : \(3\dfrac{1}{4}\text{ inches}=\dfrac{13}{4}\text{ inch}\)
The length of moth = \(3\dfrac{1}{2}\text{ inches}=\dfrac{7}{2}\text{ inches}\)
To find the number of times larger is the moth than the butterfly, we divide the length of moth by the wingspan of the butterfly as :_
\(\dfrac{7}{2}\div\dfrac{13}{4}\\\\=\dfrac{7}{2}\times\dfrac{4}{13}=\dfrac{14}{13}=1\dfrac{1}{13}\)
Hence, the moth is \(1\dfrac{1}{13}\) times larger than the butterfly.
