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Jrbs11215
Jrbs11215 Jrbs11215
  • 16-08-2016
  • Mathematics
Answered

solve
|-4b-8|+|-1-b^2|+2b^3. b= -2
show steps please .

Verified Answer :

Anonymous Anonymous
  • 16-08-2016

Ok, first put in the -2 for each b. That gives:
|-4(-2)-8|+|-1(-(-2))^2|+2(-2)^3
Let's do each section.
The first section is |-4(-2)-8)|
-4 times -2 is 8, minus 8 is 0. The absolute value of 0 is still 0.
Now we move on to |-1(-(-2))^2)|
First we do exponents
-(-2) is 2, and 2^2 is 4. 4 times -1 is -4. The absolute value of -4 is 4
Now the last section, 2(-2)^3
Exponents first: (-2)^3 is -2 -2 -2, which is -8.
-8*2=-16.
0+4+(-16)=-12

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