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Sco2ttkesbayla
Sco2ttkesbayla Sco2ttkesbayla
  • 16-08-2016
  • Chemistry
Answered

How many potassium hydroxide (KOH) formula units are present in 6.89 mol of KOH?

A4.1498 × 1024
B4.1498 × 1023
C8.299 × 1024
D8.299 × 1023

Verified Answer :

mpanderla95
mpanderla95 mpanderla95
  • 16-08-2016

I believe there would be A. 4.1498x10^24 formula units in 6.89 moles of KOH.

Answer Link
taskmasters
taskmasters taskmasters
  • 19-08-2016

Avogadro's number
represents the number of units in one mole of any substance. This has the value
of 6.022 x 10^23 units / mole. This number can be used to convert the number of formula units or atoms or molecules into number of moles.

6.89 mol KOH (6.022 x 10^23 formula units / mole) = 4.1498 x 10^24 formula units

Therefore, the correct answer is option A.

Answer Link

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