How many grams are in 882 μg?
882 μg ( 1 g / 10^6 μg) = 8.82 x 10^-4 g
The density of gold is 19.3 g/cm3Answer the following:
a. What is the volume, in cubic centimeters, of a sample of gold with mass 0.715 kg?
0.715 kg ( 1000 g / 1 kg ) ( 1cm^3 / 19.3 g ) = 37.05 cm^3
b. If this sample of gold is a cube, how long is each edge in centimeters?
V = s^3 = 37.05 cm^3
s = 3.33 cm
