Verified Answer :

dalendrk

The midpoint of AB where \(A(x_A;\ y_A)\) and \(B(x_B;\ y_B)\)

\(\left(\dfrac{x_A+x_B}{2};\ \dfrac{y_A+y_B}{2}\right)\)

\(A(7;\ 5);\ B(7;\ 11)\)

The midpoint of AB: \(\left(\dfrac{7+7}{2};\ \dfrac{5+11}{2}\right)=\left(\dfrac{14}{2};\ \dfrac{16}{2}\right)=(7;\ 8)\)

Answer: (7, 8)

meerkat18

The midpoint of two points can be obtained by taking the average between the two abscissas or two ordinates. In this case ,the x-value of the midpoint is equal to (7+7)/2 equal to 7 while the y-value of the midpoint is equalto (5+11)/2 equal to 8. Hence the midpoint is t (7,8)

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