Answer : The conjugate base of propanoic acid, \(CH_3CH_2COOH\) is, \(CH_3CH_2COO^-\)
Explanation :
According to the conjugate acid-base pair theory, an acid is a proton donor and a base is a proton acceptor.
The balanced conjugate acid-base pair reaction will be,
\(CH_3CH_2COOH+H_2O\rightleftharpoons H_3O^++CH_3CH_2COO^-\)
In this reaction, \(CH_3CH_2COOH\) is a weak acid which donate a proton to \(H_2O\) which is a weak base to form \(CH_3CH_2COO^-\) as a conjugate base and \(H_3O^+\) as a conjugate acid.
Hence, the conjugate base of propanoic acid, \(CH_3CH_2COOH\) is, \(CH_3CH_2COO^-\)
