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There are a number of ways
to express concentration of a solution. This includes molarity. Molarity is
expressed as the number of moles of solute per volume of the solution. For this we need the neutralization reaction of HCl and NaOH which is:

HCl + NaOH = NaCl + H2O

Calculation is as follows:

Molarity of NaOH = (0.132 M HCl)(.0174 L)(1 mol NaOH / 1 mol HCl ) / .025 L solution = 0.1 mol NaOH / L = 0.1 M

Explanation:

The given data is as follows.

      \(V_{1}\) = 25 ml,     \(V_{2}\) = 17.4 ml

      \(M_{1}\) = ?,          \(M_{2}\) = 0.132 M

Therefore, calculate molarity of the solution as follows.

         \(M_{1}V_{1} = M_{2}V_{2}\)

        \(M_{1} \times 25 ml = 0.132 M \times 17.4 ml\)

           \(M_{1}\) = 0.091 M

Thus, we can conclude that the concentration (in molarity) of NaOH solution is 0.091 M.

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