Verified Answer :

Answer:

For both options a and b the work done is 7200 ft lb.  

Step-by-step explanation:

Given : A 360 LB gorilla climbs a tree to a height of 20 ft.

To Find : The work done if the gorilla reaches that height in a) 10 seconds b) 5 seconds ?

Solution :

Work done is defined as the change in the energy of the gorilla must equal the net work done by the gorilla in climbing.

We have given,

Weight = 360 LB and height = 20 ft.

The work done is defined as

\(W=\int\limits^{20}_{0} {360} \, dx\)

\(W=[360x]^{20}_{0}\)

\(W=360(20)-360(0)\)

\(W=7200ft\ lb\)

Therefore, For both options a and b the work done is 7200 ft lb.

(a): The work done in 10 seconds is, 7200 ft-lb

(b): The work done in 5 seconds is, 7200 ft-lb

Work Done:

The formula for the work done is the dot product of force and displacement that is,

\(W=F \cdot D\)

Given that,

The weight of the gorilla is 360 LB

The height of the tree is 20ft

Part(a):

The work done in 10 seconds is,

\(W=F \cdot D\\W=(360)(20)\\W=7200 ft-lb\)

Part(b):

The work done in 5 seconds is,

\(W=F \cdot D\\W=(360)(20)\\W=7200 ft-lb\)

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