Answer:
value of the discriminant for the quadratic equation is, -7
Step-by-step explanation:
A quadratic equation is in the form of : \(ax^2+bx+c = 0\) ...[1]
then the discriminant(D) is given by:
\(D = b^2-4ac\)
Given the quadratic equation:
\(0 = x+2+x^2\)
We can write this as:
\(x^2+x+2 = 0\)
On comparing with [1] we have;
a = 1, b =1 and c = 2
then;
\(D = 1^2-4(1)(2) = 1-8 = -7\)
Therefore, the value of the discriminant for the quadratic equation is, -7
