solve for x. 5(x 1) = 4(x 8)
asssuming blanks are plus5(x+1)=4(x+8)distributea(b+c)=ab+ac5(x+1)=5x+54(x+8)=4x+325x+5=4x+32minus 4x from both sidesx+5=32minus 5 from both sidesx=27