Answer:
\(8a-1+0.5b=6\) when \(a=\frac{1}{4}\) and b=10.
Step-by-step explanation:
Given : Expression \(8a-1+0.5b\) when \(a=\frac{1}{4}\) and b=10.
To find : Solve the expression?
Solution :
Step 1 - Write the expression,
\(8a-1+0.5b\)
Step 2 - Substitute \(a=\frac{1}{4}\) and b=10
\(8a-1+0.5b=8(\frac{1}{4})-1+0.5(10)\)
Step 3 - Solve,
\(8a-1+0.5b=2-1+5\)
\(8a-1+0.5b=6\)
Therefore, \(8a-1+0.5b=6\) when \(a=\frac{1}{4}\) and b=10.
