When Mrs. Myles gave a test, the scores were normally distributed with a mean of 72 and a standard deviation of 8. This means that 95% of her students scored between which two scores?
Given a standardized test with a mean score of 78 and a standard deviation of 5.9, a student who scored in the 60th percentile could have a score of:
a. 84
b. 72
c. 79
d. 76
the answer is c
Answer:
The score of Mr.Myles is between 56 and 88.
Step-by-step explanation:
Given : When Mrs. Myles gave a test, the scores were normally distributed with a mean of 72 and a standard deviation of 8.
To find : The class interval at 95% of her students scored between which two scores?
Solution :
We have given,
Mean \(\mu=72\)
Standard deviation \(\sigma=8\)
The class interval at 95% is given by
\(\mu-2\sigma\leq CI\leq \mu+2\sigma\)
Substitute the values in the formula,
\(72-2(8)\leq CI\leq 72+2(8)\)
\(72-16\leq CI\leq 72+16\)
\(56\leq CI\leq 88\)
Therefore, The score of Mr.Myles is between 56 and 88.