Verified Answer :

frika

First, simplify the expression \(2r^2 + 3s^3 - r^2 + 4t^2 - r^2.\) Here you have three terms with \(r^2,\) group them in the following way:

\(2r^2 + 3s^3 - r^2 + 4t^2 - r^2=2r^2-r^2-r^2+3s^3+4t^2=(2r^2-r^2-r^2)+3s^3+4t^2=\)

\(=r^2(2-1-1)+3s^3+4t^2=3s^3+4t^2.\)

Then substitute s=-3 and t=5:

\(3s^3+4t^2=3\cdot (-3)^3+4\cdot 5^2=3\cdot (-27)+4\cdot 25=-81+100=19.\)

Answer: 19.

Answer:

19

Step-by-step explanation:

Given the formula:

2r^2 + 3s^3 − r^2 + 4t^2 − r^2  

Replace with these values r = −2, s = −3, and t = 5 and compute the result.

2(-2)^2 + 3(-3)^3 − (-2)^2 + 4(5)^2 − (-2)^2  =

= 24 + 3(-27) - 4 + 4*25 - 4 =

= 8 - 81 - 4 + 100 - 4 =

= 19

Related Questions