Answer:
Acceleration of the object on mars, \(a=3.75\ m/s^2\)
Explanation:
It is given that,
The weight of an object on Earth is, W = 350 newtons.
The acceleration due to gravity on the Earth, \(g=9.8\ m/s^2\)
Let m is the mass of the object. Weight of an object is equal to the product of mass and acceleration due to gravity.
\(m=\dfrac{W}{g}\)
\(m=\dfrac{350\ N}{9.8\ m/s^2}\)
m = 35.71 Kg
The weight of the object on mars, W' = 134 N
Mass of an object is the amount of matter contained it. It remains the same at every location. So,
\(a=\dfrac{W'}{m}\)
\(a=\dfrac{134\ N}{35.71\ kg}\)
\(a=3.75\ m/s^2\)
So, the acceleration of the object on the surface of mars is \(3.75\ m/s^2\). Hence, this is the required solution.
