candylandkhung candylandkhung

15-08-2016
Mathematics

Answered

solve the following equation: cos^2(2x)-sin^2(2x)=0

Verified Answer :

15-08-2016

Hello,

since \(cos^2{a}-sin^2{a}=cos(2a)\)

cos^2(2x)-sin^2(2x)=0
==>cos(4x)=0
==>4x=π/2+kπ
==>\(x= \dfrac{\pi}{8} + \dfrac{k\pi}{4}\)

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