b1iapigaleeElsiemar
Answered

Which relationship shows an inverse variation?

Choices:

x = 1, 2, 3, 4

y = 3, 6, 9, 12

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x = 1, 2, 3, 4

y = 60, 30, 20, 15

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x = 1, 2, 3, 4

y = 15, 13, 11, 9

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x = 1, 2, 3, 4

y = 6, 11, 20, 35

Verified Answer :

apologiabiology

in inverese, when x increases, y deceases, when x decreases, y increses

we see that x increases for all choices

therefor the y values of the answer should be decreasing

first one is increasing, wrong
second is decreasing
third is also decreasing
fourth is increasing


look at second and third

remember
xy=k for inverse
so just solve for k for each and see if it is valid

second
1,60
(1)(60)=k
60=k

2,30
(2)(30)=60
60=60
true

therefor this is nswer



2nd option is answer

boffeemadrid

The relationship that shows inverse variation is required.

The second relationship shows inverse variation.

In an inverse variation the product of x and y is constant

\(xy=k\)

Let us check each option

\(1\times 3=3\)

\(2\times6=12\)

Not an inverse variation

\(1\times 60=60\)

\(2\times 30=60\)

\(3\times 20=60\)

\(4\times 15=60\)

It is an inverse variation

\(1\times15=15\)

\(2\times13=26\)

Not an inverse variation

\(1\times6=6\)

\(2\times11=22\)

Not an inverse variation.

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