Verified Answer :

Ionic equation is:

Cu+1 + ClO4-1 + 2Na+1 + S-2 ----> CuS(s) + 2Na+1 + 2ClO4-1

If we balance the both sides to get the net ionic equation:

Cu+1 + S-2 ---- > CuS(s) + ClO4-1

I hope it helped

IthaloAbreu

Answer:

Cu²⁺(aq) + 2(ClO₄)⁻(aq) +  2Na⁺(aq)  + S²⁻(aq) → CuS (s) + 2Na⁺(aq) + 2(ClO₄)⁻(aq)

Explanation:

The net ionic equation is the equation of the ions that are dissolved in liquid. In this case water, because of the phase aqueous (aq). So, the aqueous ionic compounds will be a break in their ions, which can be made by changing the subscript to be the charge of the other ion:

Cu(ClO₄)₂   → Cu²⁺ + (ClO₄)⁻

Na₂S  →  Na⁺  + S²⁻

NaClO₄ → Na⁺ + (ClO₄)⁻

So, the reaction must be:

Cu²⁺(aq) + 2(ClO₄)⁻(aq) +  2Na⁺(aq)  + S²⁻(aq) → CuS (s) + 2Na⁺(aq) + 2(ClO₄)⁻(aq)

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