Verified Answer :

Ckaranja

The general equation of a circle is given by;
\((x-a)^{2}+ (y-b)^{2} = r^{2}\)
Where (a, b) is the centre of the circle and r is the radius. 
For the given circle, centre is (0,0) and r=11
\((x-0)^{2} + (y-0)^{2} = 11^{2}\)
\(x^{2} + y^{2} = 11^{2}\)

taskmasters

The general equation of a circle is expressed as:

(x-a)^2+ (y-b)^2  = r^2

Where the point (a, b) is the center of the circle and r is the radius. 
For the given circle, center is (0,0) and r=11

Therefore, the equation of the circle would be:
(x)^2+ (y)^2 = 11^2
(x)^2+ (y)^2 = 121

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