Answered

Evaluate the function at the specified value of the independent variable and simplify.

q(t) = (5t^2 + 6) / (t^2)

  1. Evaluate q(2)
  2. Evaluate q(0)
  3. Evaluate q(−x)

Verified Answer :

dalendrk

\(q(t)=\dfrac{5t^2+6}{t^2}\\\\1.\\q(2)=\dfrac{5\cdot2^2+6}{2^2}=\dfrac{5\cdot4+6}{4}=\dfrac{20+6}{4}=\dfrac{26}{4}=7.5\\\\2.\\q(0)=\dfrac{5\cdot0^2+6}{0^2}=\dfrac{6}{0}-unde fined\\\\3.\\q(-x)=\dfrac{5\cdot(-x)^2+6}{(-x)^2}=\dfrac{5x^2+6}{x^2}\)

Related Questions