Given the equation 2 Square root of x minus 5 = 2, solve for x and identify if it is an extraneous solution.
A.) x = 6, solution is not extraneous
B.) x = 6, solution is extraneous
C.) x = 11, solution is not extraneous
D.) x = 11, solution is extraneous
A.) x = 6, solution is not extraneous
B.) x = 6, solution is extraneous
C.) x = 11, solution is not extraneous
D.) x = 11, solution is extraneous