Verified Answer :

caylus

Hello,

\(a^3-b^3=(a-b)(a^2+ab+b^2)\\ Here\ a=x \ and \ b=11\)

x^3-11^3=(x-11)(x²+11x+121)
Answer A
I haven't read the question : x-11 is a factor! sorry.

frika

Use formula for difference of perfect cubes:

\(a^3-b^3=(a-b)(a^2+ab+b^2).\)

Consider expression \(x^3-1331.\) You know that \(1331=11^3,\) then

\(x^3-1331=x^3-11^3=(x-11)(x^2+11x+121).\)

The quadratic trinomial \(x^2+11x+121\) cannot be factored anymore, so the expression \(x^3-1331\) has two factors \(x-11\) and  \(x^2+11x+121.\)

Answer: correct choice is A.

Related Questions