Answer:
Length of edge of original block =5 inches
Step-by-step explanation:
We are given that one dimension of a cube is increased by 1 inches to form a rectangular block.
Volume of new block means rectangular block=150 cubic inches
We have to find the value of edge of the original block
Let edge length of original block=x
Length of rectangular block=x+1
Breadth of rectangular block=x
Height of rectangular block=x
Volume of rectangular block=\(length\times breadth\times height\)
Substitute the values then we get
\(150=(x+1)\times x\times x\)
\(x^2(x+1)=150\)
\(x^3+x^2=150\)
\(x^3-5x^2+6x^2-30x+30x-150=0\)
\(x^2(x-5)+6x(x-5)+30(x-5)=0\)
\((x-5)(x^2+6x+30)=0\)
\(x-5=0\)
x=5 and \(x^2+6x+30=0\)
For second quadratic equation
\(D=b^2-4ac\)
\(D=(6)^2-4\times 1\times 30\)
\(D=36-120=-84<0\)
Therefore, the roots of second quadratic equation are imaginary .
It is not possible, because we are finding length of edge of original block. Length is always is a natural number.
So, we take x=5 only
Hence,length of an edge of original block=5 inches
