Length of the rectangle = 490 yards
Width of the rectangle = 50 yards
Given :
The perimeter of the rectangular playing field is 490 yards.
Let 'w' be the width of the rectangle
Length is 5 yards less than the quadruple the width
length = 4 times width -5
\(Length (L)=4w-5\)
Perimeter of rectangle = 2(length + width )
Replace the length and width
\(Perimeter =2(L+W)\\P=2(4w-5+w)\\P=2(5w-5)\\P=10w-10\)
Given perimeter is 490 yards. Replace perimeter by 490
\(490=10w-10\\490+10=10w\\500=10w\\Divide \; by \; 10\\w=50\)
Length =\(4w-5=4(50)-5=195\)
Length of the rectangle = 490 yards
Width of the rectangle = 50 yards
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