Answer:
Step-by-step explanation:
The equations are:
\(4x-6y=28\) (1)
\(8x-4y=24\) (2)
Taking the equation(1) and then solving it to get the value of x
⇒\(4x-6y=28\)
⇒\(2x-3y=14\)
⇒\(x=\frac{14+3y}{2}\)
Now, substituting the value of x in equation (2), we get
⇒\(8(\frac{14+3y}{2})-4y=24\)
⇒\(56+12y-4y=24\)
⇒\(8y=-32\)
⇒\(y=-4\)
Putting the value of y in equation (1), we get
⇒\(4x-6(-4)=28\)
⇒\(x=1\)
Therefore, the values of x and y are 1 and -4 respectively.
